Question #8be2a

1 Answer
Feb 12, 2017

ln(ab)-1ln(ab)1

Explanation:

Consider the sum of the terms, ln(1/e)+ln(ab)ln(1e)+ln(ab)

The function lnln here is defined as a function that for whatever value you enter, you get the supposed number of times you're supposed to multiply the number ee with itself.

In simple terms, ln(x)ln(x) equals yy, where yy is such a number that when e*e*e*.....*e*e for y times (or in short e^y) gives back x to us.

Take note of the first term given in the sum. ln(1/e).
1/e can be re-written as e^-1
So, ln(1/e)=ln(e^-1)

Another important identity of ln function is that if we have a y=x^m, then ln(y)=ln(x^m)=mlnx AAm inRR

So, ln(e^-1)=-1*lne and if you remember what I typed up in the third paragraph, then you'll realize that lne=1, so ln(1/e)=-1

ln(ab) can't be simplified further than it is, so we'll have to keep it that way.

Replacing the term for ln(1/e) with what we've got, we come to the conclusion as written in the "answers" part.