Question #7738f
1 Answer
Explanation:
To graph these
#color(blue)"linear equations"# we can find the
#color(blue)"x and y intercepts".# When a line crosses the y-axis, the value of the corresponding x-coordinate is zero.
Substituting x = 0 into the equation gives us the value of the
#color(blue)"y-intercept"# Similarly when the line crosses the x-axis, the y-coordinate is zero and substituting y = 0 into the equation gives the value of the
#color(blue)"x-intercept"#
#color(blue)" equation :" x-y=-2#
#x=0to0-y=-2toy=2larrcolor(red)" y-intercept"#
#y=0tox-0=-2tox=-2larrcolor(red)"x-intercept"# Plot the points (0 ,2) and (-2 ,0) and draw a straight line through them.
#color(blue)"equation :"x+y=8#
#x=0to0+y=8toy=8larrcolor(red)"y-intercept"#
#y=0tox+0=8tox=8larrcolor(red)"x-intercept"# On the same grid as the previous points, plot (0 ,8) and (8 ,0)
The solution to the system is at
#color(blue)" the point of intersection of the 2 lines"#
graph{(y-x-2)(y+x-8)=0 [-10, 10, -5, 5]}
