Question #d3e91

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Question #d3e91

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Answer 1 · 2017-01-23T18:00:54

$6$ $6$

Explanation:

If you want an even number, the number would have to end in an even number. The only even number we have in the above list is $2$ $2$ .

We are left with $3$ $3$ numbers. When we pick the first number, there will be $3$ $3$ numbers left. When we pick the second number, there will be $2$ $2$ numbers left. When we pick the third number, there will only be $1$ $1$ number left.

Therefore, the number of numbers that can be formed is given by $3! \cdot 1 = 3 \cdot 2 \cdot 1 \cdot 1 = 6$ $3! * 1 = 3 * 2 * 1 * 1 = 6$ , where $n! = n(n - 1)(n - 2)(...)(1)$ .

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