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Question #33ba6

1 Answer

Jan 22, 2017

Approx. #15-16*g#.

Explanation:

#"Concentration"# #=# #"Moles"/"Volume"#

And thus #"moles"# #=# #"concentration"# #xx# #"volume"#

#"moles"# #=# #0.280*mol*cancel(L^-1)xx275xx10^-3*cancelL#

#=0.0770*mol#

And thus we need a mass of #0.0770*molxx208.3*g*mol^-1#

#=# #??*g#

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