Question #0297a

1 Answer
anor277
Jan 9, 2017

"Molarity"="0.4 mol"*"L"^-1

Explanation:

"Molarity"="Moles of solute"/"Volume of solution"

=(2*"mol")/(0.500*"L")=0.4*"mol"*"L"^-1.

So two questions for you:

(i) What is the concentration in "g"*"L"^-1?

(ii) What are (i) the "pOH", and (ii) the "pH" of this solution?

Related questions
See all questions in Molarity
Impact of this question
1619 views around the world
You can reuse this answer
Creative Commons License