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Question #0297a

1 Answer

Jan 9, 2017

#"Molarity"="0.4 mol"*"L"^-1#

Explanation:

#"Molarity"="Moles of solute"/"Volume of solution"#

#=(2*"mol")/(0.500*"L")=0.4*"mol"*"L"^-1#.

So two questions for you:

(i) What is the concentration in #"g"*"L"^-1#?

(ii) What are (i) the #"pOH"#, and (ii) the #"pH"# of this solution?

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