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Question #4a240

1 Answer

Dec 18, 2016

#V_2~=40*L#

Explanation:

#(P_1V_1)/T_1=(P_2V_2)/T_2#

All temperature is reported on the #"Absolute scale"#; for #"pressure"# we use the relationship #760# #mm# #Hg# #-=# #1*atm.#

#V_2=T_2/(P_2)xx(P_1V_1)/T_1=(256.8*K)/((385*mm*Hg)/(760*mm*Hg*atm^-1))xx1/(303.5*K)xx((731*mm*Hg)/(760*mm*Hg*atm^-1))xx26.5*L~=40*L#

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