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Question #69a2e

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Dec 14, 2016

Given #r^2 = theta#

The breaks into 3 equations depending on the value of x and y:

#x^2 + y^2 = tan^-1(y/x); x > 0, y > 0#

#x^2 + y^2 = pi + tan^-1(y/x); x < 0#

#x^2 + y^2 = 2pi + tan^-1(y/x); x > 0, y < 0#

#x = 0# when you choose #y = 0# but not the vice-versa.

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