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Solve the equation $sin x cos x = 0$ $sinxcosx=0$ ?

1 Answer

Shwetank Mauria

Dec 27, 2016

$x = \frac{n π}{2}$ $x=(npi)/2$ , where $n$ $n$ is an integer.

Explanation:

$sin x cos x = 0$ $sinxcosx=0$

i.e. $2 sin x cos x = 0$ $2sinxcosx=0$ or $sin 2 x = 0$ $sin2x=0$

Hence $2 x = n π$ $2x=npi$ , where $n$ $n$ is an integer.

Hence, $x = \frac{n π}{2}$ $x=(npi)/2$ , where $n$ $n$ is an integer.

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