Question #0b46c

1 Answer
Jan 3, 2017

Here's how I would do it.

Step 1. Draw a 10-carbon (decane) chain.

1
#"decane"#

Step 2. Number the carbons from left to right.

Attach an isopropyl group to carbon 4.

2
#"4-isopropyldecane"#

Step 3. Attach a sec-butyl group to carbon 5.

3
#"4-isopropyl-5-sec-butyldecane"#

And you have the structure.