Question #6e801

1 Answer
Stefan V.
Dec 1, 2016

Here's what I got.

Explanation:

Assuming that your solution contains "1 g"1 g of solute in "100 mL"100 mL of solution, you can say that it has a 1%1% mass by volume percent concentration, i.e. "1% m/v"1% m/v.

A solution's mass by volume percent concentration is calculated by looking at how many grams of solute you get for every "100 mL"100 mL of solution.

In this case, you know that "100 mL"100 mL of solution contains "1 g"1 g of solute, so its mass by volume percent concentration will be "1% m/v"1% m/v.

How about a solution that contains "1 g"1 g of solute in "50 mL"50 mL of solution, what would its mass by volume percent concentration be?

100 color(red)(cancel(color(black)("mL solution"))) * overbrace("1 g solute"/(50color(red)(cancel(color(black)("mL solution")))))^(color(blue)("known composition")) = "2 g solute"

This means that the solution is "2% m/v", since it contains "2 g" of solute for every "100 mL" of solution.

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