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Question #25bda

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1 Answer

Nov 29, 2016

#sqrt(x^2-5x+5)=1#

#=>x^2-5x+5=1#

#=>x^2-5x+4=0#

#=>x^2-4x-x+4=0#

#=>x(x-4)-1(x-4)=0#

#=>(x-4)(x-1)=0#

So #x=4 and x=1#

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