Question #79774

1 Answer
anor277
Nov 29, 2016

#[HO^-]=3.98xx10^-11*mol*L^-1#

Explanation:

#[H_3O^+]=(3.00xx10^-3*mol)/(12*L)=2.5xx10^-4*mol*L^-1#

#pH=-log_10[H_3O^+]=-log_10(2.5xx10^-4)=-(-3.60)=3.60#

Since #pH+pOH=14#, #pOH=10.40#,

And now we take anti-logs.......

#[HO^-]=10^(-10.4)*mol*L^-1=3.98xx10^-11*mol*L^-1#

Hydroxide ion concentration is low, because this is an acidic solution.

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