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Question #f70db

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Nov 30, 2016

$\frac{b + a c}{a b^{3} c}$ $(b + ac)/(ab^3c)$

Explanation:

Pull out the greatest common factor of each term. In this case $a^{2} b$ $a^2b$ giving:

$\frac{(a^{2} b) \cdot b + (a^{2} b) (a c)}{(a^{2} b) a b^{3} c} \to$ $((a^2b)*b + (a^2b)(ac))/((a^2b)ab^3c) ->$

$\frac{(a^{2} b) (b + a c)}{(a^{2} b) a b^{3} c} \to$ $((a^2b)(b + ac))/((a^2b)ab^3c) ->$

$(cancel((a^2b))(b + ac))/(cancel((a^2b))ab^3c) ->$

$(b + ac)/(ab^3c)$

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