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Question #7c1c3

1 Answer

Nov 22, 2016

#12=3^y#

Explanation:

Using the #color(blue)"law of logarithms"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=nhArrx=b^n)color(white)(2/2)|)))#

#"For" log_3 12=y#

#rArr12=3^y#

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