Question #7c1c3
1 Answer
Nov 22, 2016
Explanation:
Using the
color(blue)"law of logarithms"
color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=nhArrx=b^n)color(white)(2/2)|)))
"For" log_3 12=y
rArr12=3^y