Question #86931

1 Answer
Nov 22, 2016

When the hollow sphere with a small hole is immersed in water a thin film of water is formed at the mouth of the hole.This film acts as a membrane and prevents water to enter in the hollow sphere.

With increase in depth of immersion the pressure on this film goes to increase and slowly it acquires spherical shape and when a spherical droplet of diameter equal to the diameter of the hole is formed, water starts to enter into the cavity of hollow sphere. At this moment the excess pressure within the the spherical droplet of water becomes equal to the hyodrostatic pressure of water column at the depth of water that hole reaches.

The extra pressure within the droplet due to surface tension Pst=2γr
Where
γsurface tension of water=0.07Nm

=0.07×105dyne100cm=70dyne/cm

rradius of the hole=?

The hydrostatic pressure at h depth of water

Phy=h×d×g

where
hdepth of water=40cm

ddensity of water=1gcm3

gacceleration due to gravity=980cms2

By the condition

Pst=Phy

2γr=h×d×g

r=2γh×d×g

r=2×7040×1×980cm3.57×103cm

So diameter of the hole =2×r=7.14×103cm