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Answer 1 · 2016-11-10T16:04:11

The given sample of vinegar is 5.1% acetic acid by mass.

This means #100g# acetic acid contains #5.1g# acetic acid.

It is assumed tha density of vinegar is#=1" g/mL"#

So we can say

#100mL or 0.1L # Vinegar contains # 5.1g# acetic acid.

So the strength of vinegar solution is #=5.1xx10=51gL^-1#

Now molar mass of #CH_3COOH#

#=2*12+2*16+4*1=60" g/mol"#

So strength of the acetic acid solution

#S_1=(51g/L)/(60g/"mol")=0.85M#

Volume of acetic acid solution

#V_1=5mL#

Let this solution is nutralised by #NaOH# solution of strength #S_2=0.22M# and of Volume #V_2mL#

The balanced equation of nutralisation reaction is

#CH_3COOH +NaOH->CH_3COONa+ H_2O#

This equation reveals that the stochiometric ratio of reactants is #1:1#

So this follows the relation

#S_2xxV_2=S_1xxV_1#

#=>0.22xxV_2=0.85xx5#

#=>V_2=(0.85xx5)/0.22=19.3mL#