How many 3d_(z^2)3dz2 orbitals have n = 3n=3 and l = 2l=2?
1 Answer
Nov 9, 2016
You already specified an orbital, so... one...
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bb(n = 3)n=3 , because the33 in front says that. Thus, it is in the 3rd quantum level.bb(l = 2)l=2 , which corresponds to add orbital, since the values ofll correspond as(0,1,2,3,4, . . . ) harr (s,p,d,f,g, . . . )(0,1,2,3,4,...)↔(s,p,d,f,g,...) .m_lml for this orbital is one of the values in the following set:{-2,-1,0,+1,+2}{−2,−1,0,+1,+2} . It does not matter which one, but it is only one of them, since you have specified only onedd orbital. That is,m_lml is known, but is yours to choose, since all the3d3d orbitals in an atom are the same energy (degenerate).m_sms requires more information to specify, but it can either bepm"1/2"±1/2 in general. It depends on how many electrons were in that orbital to begin with, whether it's spin-up or spin-down for the electron of choice.