Question #b05eb

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Question #b05eb

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Answer 1 · 2017-12-13T00:06:05

The period is #pi/2#

Explanation:

The expression has the form #2sin(A)cos(A)# where #A=2x#.

#sin(2A)=2sin(A)cos(A)#, so we can rewrite the given expression as #sin(4x)#. The period of a sine function is #P=(2pi)/B#, where #B# is the coefficient of #x#, so the period is #(2pi)/4=pi/2#.

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