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Answer 1 · 2016-10-26T16:44:59

Given quadratic equation of m is

#2m^2-16m+8=0#

#=>m^2-8m+4=0#

It being a quasratic equation it will have only two values that satisfy the equation. Let these are a and b.

So #(m-a)(m-b)=0# should be the qudratic equation.

Comparing these two equations
we have

#(m-a)(m-b)=m^2-8m+4#

#m^2-(a+b)m+ab=m^2-8m+4#

Comparing LHS and RHS we get

#a+b=8#

~~~~~~~~~~~~~~~~~~~~~~~~~~±~
For any quadratic equation

#ax^2+bx+c=0#,

if #alpha and beta # are two values of x that satisfy the equation then

#alpha+beta=-b/a and alphabeta=c/a#