Question #ae517

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Question #ae517

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Answer 1 · 2016-10-24T22:30:35

$x=+-2sqrt(7)$

Explanation:

$f(x) = g(x)$

$=> x+5 = 3/(x-5)$

$=> (x+5)(x-5) = 3$

$=> x^2 - 25 = 3$

At this point it would be simplest to just add $25$ to both sides and take a square root, but as the question refers to the quadratic formula, we will instead put it in standard form and proceed in that manner.

$=> x^2 - 28 = 0$

$=> 1x^2 + 0x - 28 = 0$

$=> x = (-0+-sqrt(0^2-4(1)(-28)))/(2(1))$

$=(+-4sqrt(7))/2$

$=+-2sqrt(7)$

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Question #ae517

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