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Question #57649

1 Answer

Oct 22, 2016

An Arrhenius acid produces $H^{+}$ $"H"^+$ ions in solution and an Arrhenius base produces ${OH}^{-}$ $"OH"^-$ ions in solution.

Explanation:

${HCl}_{(aq)} \to H^{+} + {Cl}^{-}$ $"HCl"_"(aq)" rarr "H"^+ +"Cl"^-$

In this case, "HCl" is an Arrhenius acid because it produces $H^{+}$ $"H"^+$ in solution.

${NaOH}_{(aq)} \to {Na}^{+} + {OH}^{-}$ $"NaOH"_"(aq)" rarr "Na"^+ + "OH"^-$

In this case, "NaOH" is an Arrhenius acid because it produces ${OH}^{-}$ $"OH"^-$ in solution.

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