Given $1.0 \cdot m o l \cdot L^{- 1}$ $1.0molL^-1$ solutions of $N a C l (a q)$ $NaCl(aq)$ , what are the masses of solute in.....?

Question

Given $1.0 \cdot m o l \cdot L^{- 1}$ $1.0molL^-1$ solutions of $N a C l (a q)$ $NaCl(aq)$ , what are the masses of solute in.....?

$(i)$ $(i)$ $a 1 L volume of solution;$ $"a 1 L volume of solution;"$
$(i i)$ $(ii)$ $a 250 mL volume of solution;$ $"a 250 mL volume of solution;"$
$(i i i)$ $(iii)$ $a 100 mL volume of solution?$ $"a 100 mL volume of solution?"$

1 Answer

Impact of this question

1560 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-18T18:30:53

Well the molar mass of $N a C l$ $NaCl$ is $(22.99 + 35.45) \cdot g \cdot m o l^{- 1} =$ $(22.99+35.45)*g*mol^-1=$ $58.44 \cdot g \cdot m o l^{- 1}$ $58.44*g*mol^-1$ .......

Explanation:

From where did I get the atomic masses?

For the remaining problems, we use the relationship.....

$Concentration/Molarity = \frac{Moles of solute}{Volume of solution}$ $"Concentration/Molarity"="Moles of solute"/"Volume of solution"$

And so, if we gots a $1 \cdot L$ $1*L$ volume of $1 \cdot m o l \cdot d m^{- 3}$ $1*mol*dm^-3$ solution with respect there is a mass of.....

$1 \cdot L \times 1 \cdot m o l \cdot L^{- 1} \times 58, 44 \cdot g \cdot m o l^{- 1} = 58.44 \cdot g$ $1*Lxx1*mol*L^-1xx58,44*g*mol^-1=58.44*g$

And note that $1 \cdot d m^{3} \equiv {(1 \times 10^{- 1} \cdot m)}^{3} \equiv 1 \times 10^{- 3} \cdot m^{3} = 1 \cdot L$ $1*dm^3-=(1xx10^-1*m)^3-=1xx10^-3*m^3=1*L$ , because there are $1000 \cdot L$ $1000*L$ in a $m^{3}$ $m^3$ .

And we also gots $250 \cdot c m^{3} \times 10^{- 3} \cdot d m^{3} \cdot c m^{- 3} \cdot 2 \cdot m o l \cdot d m^{- 3} \times 58.44 \cdot g \cdot m o l^{- 1} = 29.22 \cdot g$ $250*cm^3xx10^-3*dm^3*cm^-3*2*mol*dm^-3xx58.44*g*mol^-1=29.22*g$

And I will let you the third.......

Science

Math

Humanities

... and beyond

Given $1.0 \cdot m o l \cdot L^{- 1}$ $1.0molL^-1$ solutions of $N a C l (a q)$ $NaCl(aq)$ , what are the masses of solute in.....?

$(i)$ $(i)$ $a 1 L volume of solution;$ $"a 1 L volume of solution;"$
$(i i)$ $(ii)$ $a 250 mL volume of solution;$ $"a 250 mL volume of solution;"$
$(i i i)$ $(iii)$ $a 100 mL volume of solution?$ $"a 100 mL volume of solution?"$

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

Given 1.0⋅mol⋅L−11.0*mol*L^-1 solutions of NaCl(aq)NaCl(aq), what are the masses of solute in.....?

(i)(i) a 1 L volume of solution;"a 1 L volume of solution;" (ii)(ii) a 250 mL volume of solution;"a 250 mL volume of solution;" (iii)(iii) a 100 mL volume of solution?"a 100 mL volume of solution?"

1 Answer

Explanation:

Related questions

Impact of this question

Given $1.0 \cdot m o l \cdot L^{- 1}$ $1.0molL^-1$ solutions of $N a C l (a q)$ $NaCl(aq)$ , what are the masses of solute in.....?

$(i)$ $(i)$ $a 1 L volume of solution;$ $"a 1 L volume of solution;"$
$(i i)$ $(ii)$ $a 250 mL volume of solution;$ $"a 250 mL volume of solution;"$
$(i i i)$ $(iii)$ $a 100 mL volume of solution?$ $"a 100 mL volume of solution?"$