What mass of lithium hydroxide is need to prepare a #250mL# volume of #"LiOH"# at #0.33mol*L^-1# concentration?

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Answer 1 · 2016-10-24T16:32:30

We require an approximate mass of #2.0*g# of #LiOH#.

#"Concentration"# #=# #"Moles of solute"/"Litres of solution"#. And thus the typical units of concentration are #mol*L^-1#.

We want to make a #250*mL# volume of #0.33*mol*L^-1# concentration. And thus we need #0.250*Lxx0.33*mol*L^-1# #=# #0.0825*mol# of #LiOH# solute.

And this molar quantity has a mass of #0.0825*molxx23.95*g*mol^-1# #=# #1.98*g#

What mass of lithium hydroxide is need to prepare a #250*mL# volume of #"LiOH"# at #0.33*mol*L^-1# concentration?