What mass of sodium chloride is present in a $250mL$ volume of $5.0mol*L^-1$ $NaCl(aq)$ ?

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Answer 1 · 2016-10-15T16:32:09

$"Mass of NaCl"~=75*g$

We use the relationship:

$"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$

We know $"Concentration"$ and $"Volume"$ , and thus

$"Moles of solute"$ $=$ $"Concentration"xx"Volume of solution"$

$=$ $5.0*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)$

$=$ $1.25*mol$

And a $1.25*mol$ quantity of sodium chloride has a mass of $1.25*cancel(mol)xx58.44*g*cancel(mol^-1)$ $=$ $??*g$

What mass of sodium chloride is present in a 250*mL250*mL volume of 5.0*mol*L^-15.0*mol*L^-1 NaCl(aq)NaCl(aq)?