What mass of sodium chloride is present in a 250*mL volume of 5.0*mol*L^-1 NaCl(aq)?

1 Answer
Oct 15, 2016

"Mass of NaCl"~=75*g

Explanation:

We use the relationship:

"Concentration" = "Moles of solute"/"Volume of solution"

We know "Concentration" and "Volume", and thus

"Moles of solute" = "Concentration"xx"Volume of solution"

= 5.0*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)

= 1.25*mol

And a 1.25*mol quantity of sodium chloride has a mass of 1.25*cancel(mol)xx58.44*g*cancel(mol^-1) = ??*g