What mass of sodium chloride is present in a #250mL# volume of #5.0mol*L^-1# #NaCl(aq)#?

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Answer 1 · 2016-10-15T16:32:09

#"Mass of NaCl"~=75*g#

We use the relationship:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

We know #"Concentration"# and #"Volume"#, and thus

#"Moles of solute"# #=# #"Concentration"xx"Volume of solution"#

#=# #5.0*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)#

#=# #1.25*mol#

And a #1.25*mol# quantity of sodium chloride has a mass of #1.25*cancel(mol)xx58.44*g*cancel(mol^-1)# #=# #??*g#

What mass of sodium chloride is present in a #250*mL# volume of #5.0*mol*L^-1# #NaCl(aq)#?