Question #b8942

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Answer 1 · 2016-10-13T02:38:36

Given
$vec(X)+vec(Y)=vec(R)$

So $vec(X)+vec(Y)+vec(Z)=vec(R)+vec(Z)$

Ler the angle between $vec(Z) and vec(R)$ be $theta=170^@$

Also given $abs(vec(Z))=13.5N and abs(vec(R))=19.3N$

Now $abs(vec(X)+vec(Y)+vec(Z))= abs(vec(Z)+vec(R))$

$=sqrt(abs(vec(Z))^2+ abs(vec(R))^2+2abs(vec(Z))*abs(vec(R))costheta)$

$=sqrt((13.5)^2+ (19.3)^2+2*13.5*(19.3)*cos170)$
$=6.45N$