Question #89a1e Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Henry W. Oct 27, 2016 #(dy)/(dx)=-6x^2sin(x^3)cos(x^3)# Explanation: #d/(dx)cos^2(x^3)# We have to apply chain rule, where #u=cos(x^3)# #(dy)/(du)=d/(du)u^2=2u=2cos(x^3)# #(du)/(dx)=d/(dx)cos(x^3)=-3x^2sin(x^3)# #(dy)/(dx)=(dy)/(du)*(du)/(dx)=2cos(x^3)*-3x^2sin(x^3)# #=-6x^2sin(x^3)cos(x^3)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2648 views around the world You can reuse this answer Creative Commons License