Question #871b4

Question

1406 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-15T08:19:38

you are correct

#vec(AB)=vec(AO)+vec(OB)#

#vec(AB)=-vec(OA)+vec(OB)#

putting the vectors in to column vectors for ease of formatting

#vec(AB)=-((1),(3),(p))+((-7),((1-p)) , (p))#

#vec(AB)=((-8),(-2-p),(0))#

substitute for #p#

#vec(AB)=((-8),(-2- -8),(0))=((-8),(6),(0))#

#vec(AB)=-8hatveci+6hatvecj#

#|vec(AB)|=sqrt(8^2+6^2)=10#

unit vector for #vec(AB)#

#hatvec(AB)=vec(AB)/|vec(AB)|#

#hatvec(AB)=1/10(-8hatveci+6hatvecj)=-4/5hatveci++3/5hatvecj#

which is what you got.