Question #3285c

1 Answer
P dilip_k
Sep 27, 2016

#x=25g#

Explanation:

The initial mass of the solution was 100g
As 50% (w/w) solute was present in 100g solution , we can say the mass of the solute in initial solution was 50g

After addition of x g solute in 100g solution the changed mass of solution became (x+100)g and total amount of solute became (x+50)g.
So the percentage of solute in final solution became 60%.

So

#(x+50)/(x+100)xx100=60#

#=>(x+50)/(x+100)=60/100=0.6#

#=>x+50=0.6(x+100)#

#=>x+50=0.6x+60#

#=>x-0.6x=60-50#

#=>0.4x=10#

#=>x=10/0.4=25#

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