To make a 50% solution of carbon tetrachloride in benzene, how much carbon tetrachloride should be added to $100 \cdot m L$ $100*mL$ of benzene?

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To make a 50% solution of carbon tetrachloride in benzene, how much carbon tetrachloride should be added to $100 \cdot m L$ $100*mL$ of benzene?

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Answer 1 · 2016-10-01T16:10:49

Surely you should add $100 \cdot m L$ $100*mL$ of $carbon tetrachloride$ $"carbon tetrachloride"$ ?

Explanation:

You want a $50 %$ $50%$ $\frac{v}{v}$ $v/v$ solution of $carbon tet$ $"carbon tet"$ in $benzene$ $"benzene"$ . Clearly, we should take EQUAL volumes of each solvent to prepare such a concentration. You started with a $100 \cdot m L$ $100*mL$ of benzene; you thus need a $100 \cdot m L$ $100*mL$ volume of carbon tetrachloride. The volumes should certainly be additive to a first approximation.

Could I prepare a 50% solution of $carbon tet$ $"carbon tet"$ in water? Why or why not?

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To make a 50% solution of carbon tetrachloride in benzene, how much carbon tetrachloride should be added to $100 \cdot m L$ $100*mL$ of benzene?

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To make a 50% solution of carbon tetrachloride in benzene, how much carbon tetrachloride should be added to 100⋅mL100*mL of benzene?

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To make a 50% solution of carbon tetrachloride in benzene, how much carbon tetrachloride should be added to $100 \cdot m L$ $100*mL$ of benzene?