Question #ed224

1 Answer
P dilip_k
Jan 6, 2017

Option -A

Explanation:

given

Considering the equilibrium of forces acting on the beam we can say that the moment of the applied upward force F=5N acting at P about the pivot O will be equal to the moment of the weight W about O, but they will be oppositely directed.

So

OQxxW=OPxxF

=>W=(OPxxF)/(OQ)=(OPxxF)/(OP+PQ)=(2xx5)/((2+3))=2N

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