For a litre volume, what is the mass of calcium chloride present in a 2*mM solution of CaCl_2?

1 Answer
anor277
Sep 17, 2016

A stoichiometric quantity, approx. 222 mg.

Explanation:

"Molarity" = "Moles of solute"/"Volume of solution", and thus "molarity" has units of mol*L^-1. And thus,

"Moles of solute"="Volume of solution"xx"molarity"

We have a 2"mM" solution, i.e. a 2.0xx10^-3mol*L^-1 of CaCl_2, and, clearly, there are 2.0xx10^-3mol of CaCl_2 present in solution.

Thus, with respect to CaCl_2 there are ............

1*cancelLxx2.0xx10^-3cancel(mol*L^-1)xx110.98*g*cancel(mol^-1) = 0.222*g calcium chloride. What is the concentration of this solution with respect to Cl^- ion?

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