Question #1d00a

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Answer 1 · 2016-09-15T16:29:15

Here's how to think about it.

Since a plot of #1/P_"A"# vs. #t# is linear, the reaction is second-order in #"A"#.

Therefore, you use the equations for a second-order reaction.

The integrated rate law for a second order reaction is

#color(blue)(bar(ul(|color(white)(a/a) 1/"A"_t = kt + 1/"A"_0color(white)(a/a)|)))" "#

where #"A"# represents the pressure of the gas.

The slope of the plot of #1/"A"_t# vs #t# is #k#.

For a second order reaction,

#color(blue)(bar(ul(|color(white)(a/a) t_½ = 1/(k"A"_0) color(white)(a/a)|)))" "#

Since you now know the values of #k# and #"A"_0#, you can calculate the half-life.

If #"A"_0# = 150 ppbv, 10 % of #"A"_0# = 15.0 ppbv.

Insert these values into the integrated rate law and solve for #t#.