What is the mass of calcium iodide required for a #2L# volume of calcium iodide whose concentration is #2mol*L^-1#?

Question

2124 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-06T18:02:47

If you mean #"calcium iodide"# then you need a mass of #587.78*g#.

#"Concentration"="Moles of solute"/"Volume of solution"#

And thus #"moles of solute"="concentration"xx"volume of solution"#

And from the boundary conditions of the problem:

#"moles of solute"="concentration"xx"volume"#

#"moles of solute"=2.0*mol*L^-1xx1*L=2.0*mol#.

And #"2 moles of calcium iodide"# represents a mass of #2*"mol"xx293.89* g*mol^-1=??g.#

What is the mass of calcium iodide required for a #2*L# volume of calcium iodide whose concentration is #2*mol*L^-1#?