Question #91d1f

1 Answer
P dilip_k
Sep 11, 2016

Let the density of water be 1g/(mL)

So the volume of 56g of water =56mL=0.056L

Volume of alcohol in the mixture 0.17L

So total Volume of the mixture 0.17L+0.056L=0.226L

So the concentration of water in percent by volume =0.056/0.226xx100=24.78%

And the concentration of alcohol in percent by volume (100-24.78)%=75.22%

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