Question #81d8b

1 Answer
Gió
May 31, 2017

I may be wrong on this so check it....

Explanation:

I would think that this is the probability of two events that can happen simultaneously (be even, event #A#, or in group N, event #B#) :
I would say that the probability of this event #A or B# is:

#P(AuuB)=P(A)+P(B)-P(AnnB)#

Where the last intersection probability bit is included to avoid repetitions.

We have:
#75# possible event;
#37# possibilities to come out even;
#15# possibilities to be in group N;
#7# possibilities to be in group N and be even;

so:

#P(A)=37/75=0.493#
#P(B)=15/75=0.2#
#P(AnnB)=7/75=0.093#

So:

#P(AuuB)=0.493+0.2-0.093=0.6#

or: #60%#

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