Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

If #y=sin^5x# then what is #dy/dx#?

1 Answer

Oct 4, 2016

Use the chain rule

Explanation:

If #y=sin^5x#, then Let #u=sin x#,

Then #(du)/(dx)=cosx# and #y=u^5# so #(dy)/(du)=5u^4#

Chain rule gives #(dy)/(dx)=(dy)/(du) (du)/(dx)#. so:
#(dy)/(dx)= 5u^4 cosx = 5sin^4x cos x#

Related questions

See all questions in Intuitive Approach to the derivative of y=sin(x)

Impact of this question

12651 views around the world

You can reuse this answer
Creative Commons License