Question #8f4d7

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Question #8f4d7

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Answer 1 · 2016-09-13T12:38:23

$55.8^@$ , rounded to one decimal place.

Explanation:

Given two vectors
$vecS$ , with $|vecS|=4$ and $vecR$ , with $|vecR|=6$
Let $theta$ be the angle between the two.
By definition of dot product we have
$vecS cdot vecR=|vecS||vecR|cos theta$
Equating to the given value we get
$|vecS||vecR|cos theta=13.5$
$=>4xx6cos theta=13.5$
$=>cos theta=13.5/24=0.5625$
$=> theta=cos^-1 0.5625$
$=> theta=55.8^@$ , rounded to one decimal place.

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Question #8f4d7

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