Question #e4dc9
1 Answer
Here are several possibilities.
Explanation:
The corresponding alkane would have the formula
Each ring or double bond in the molecule removes 2
Our formula is missing 6
∴
There are six possible combinations.
I will give one example of each type.
3 Double bonds
Penta-1,2,4-triene has 6
1 Triple bond + 1 double bond
Pent-3-en-1-yne has 6
1 Ring + 1 triple bond
Ethynylcyclopropane has 6
1 Ring + 2 double bonds
Cyclopenta-1,3-diene has 6
2 Rings + 1 double bond
Bicyclo[2.1.0]pent-2-ene has 6
Three rings
Tricyclo[1.1.1.0]pentane has 6