Let w gram of #KIO_3# be dissolved in water to make a solution V L.
Now molar mass of #KIO_3=39+127+3*16=214g/"mol"#
So w g #KIO_3="w g"/(214g/"mol")=w/214mol#
So the strength of this solution will be
#="no of moles of solute"/"Volume"xx1000M#
#=w/(214V)xx1000M =S (M) #
The no of moles of solute present xL solution will be #x xxS" mol"#
As the solute #KIO_3# is a strong electrolyte which dissociates in water as follows , the solution will contain same no. of moles of #IO_3^-# ions as it contains no.of moles of #KIO_3#
#KIO_3rightleftharpoonsK^+ + IO_3^-#
