What is the concentration in $"%w/v"$ of sodium sulfate when $"9.74 g"$ of it is placed into a $165$ volume?

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Answer 1 · 2017-07-26T21:27:50

Well... $165$ what? I assume $"mL"$ (because who would ever drop $"9.74 g"$ of something in a huge $"165 L"$ vat?)...

And thus, with no other assumptions...

$c_(Na_2SO_4) = ("9.74 g Na"_2"SO"_4)/("165 mL soln")$

$%w//v$ is defined for a solute mass in $"g"$ and a solution volume in $"mL"$ , so we are basically done...

$color(blue)(c_(Na_2SO_4)) = 0.0590 xx 100% = color(blue)(5.90% w//v)$

What is the concentration in "%w/v""%w/v" of sodium sulfate when "9.74 g""9.74 g" of it is placed into a 165165 volume?