Question #6cce1

1 Answer
Jim G.
Nov 11, 2016

#log_16 64=3/2#

Explanation:

Using the #color(blue)"laws of logarithms"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=n hArr x=b^n)color(white)(2/2)|)))#

Here we have #64=16^(3/2)larr" in exponential form"#

By comparison we obtain.

#x=64,b=16" and " n=3/2#

#rArrlog_16 64=3/2larr" in logarithmic form"#

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