Question #6cce1

1 Answer
Jim G.
Nov 11, 2016

log_16 64=3/2

Explanation:

Using the color(blue)"laws of logarithms"

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=n hArr x=b^n)color(white)(2/2)|)))

Here we have 64=16^(3/2)larr" in exponential form"

By comparison we obtain.

x=64,b=16" and " n=3/2

rArrlog_16 64=3/2larr" in logarithmic form"

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