Question #2420c

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Question #2420c

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Answer 1 · 2016-08-08T04:14:20

The Kb determines if a compound is a weak base or a strong base. Also the determination of pH or POH can determine if s compound is a strong or weak base.

Explanation:

A strong base has a large number of basic ions OH- in solution. A weak base has a small percentage of basic ions OH - in solution.

Ph 8-10 are weak bases, Ph 11-14 are strong bases.

H+ + OH- = 14

in water H+ = $10^{- 7}$ $10^-7$ and OH- = $10^{- 7}$ $10^-7$

At Ph 13 for example H+ = $10^{- 13}$ $10^-13$ while OH- = # 10^-1

The total must always equal $10^{- 14}$ $10^-14$

OH- $10^{- 1}$ $10^-1$ means that 1/10 molecules is a OH- ion 10% of the solution that makes it a strong base.

pH 8 means that OH- = $10^{- 8}$ $10^-8$

$10^{- 8}$ $10^-8$ = 1/00000000 of the solution are OH- ions. That makes it a weak base.

Answer 2 · 2016-08-26T01:20:07

The $K_{b}$ $K_b$ determines if a compound is a weak base or a strong base.

Explanation:

A strong base dissociates completely in solution (has a $K_{b} ≫ 1$ $K_b ≫ 1$ ).

A weak base dissociates slightly in solution (has a $K_{b} ≪ 1$ $K_b ≪ 1$ ).

A base can be a strong base, even if it contributes only a few ions to the solution.

Thus, $NaOH$ $"NaOH"$ is a strong base because it dissociates completely:

$NaOH(aq) \to {Na}^{+} (aq) + {OH}^{-} (aq)$ $"NaOH(aq)" → "Na"^+"(aq)" + "OH"^"-""(aq)"$

If you dissolve $10^{-8} l mol of NaOH$ $10^"-8" color(white)(l) "mol of NaOH"$ in 1 L of water, it will contribute only $10^{-8} l mol$ $10^"-8"color(white)(l) "mol"$ of ${OH}^{-}$ $"OH"^"-"$ ions, but that is 100 % of what it has to give.

$NaOH$ $"NaOH"$ is a strong base. Its strength does not depend on its concentration.

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Question #2420c

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