Using long division solve #(12x^2+9x-7)-:3x#?

1 Answer
Tony B
Jun 20, 2016

#4x+3-7/(3x)#

Explanation:

#(12x^2+9x-7) color(blue)(-:3x)#

#" "12x^2+9x-7#
#color(magenta)(4x)color(blue)((3x))->color(white)(.) ul(12x^2" ")larr" subtract"#
#" "0+9x-7#
#color(magenta)(3)color(blue)((3x))->" "ul(color(white)(.)9x" ")larr" subtract"#
#" "0color(magenta)(-7""larr" remainder")#
;~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(magenta)(4x+3-7/(color(blue)(3x)))#

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