What is #r sin theta = 5# in #(x,y)# coordinates ? Calculus Parametric Functions Introduction to Parametric Equations 1 Answer Cesareo R. Aug 9, 2016 #y = 5# Explanation: The pass equations are #{ (x = r cos theta), (y=r sin theta):}# so #r sin theta = y = 5# so the answer is #y = 5# Answer link Related questions How do you find the parametric equation of a parabola? How do you find the parametric equations for a line segment? How do you find the parametric equations for a line through a point? How do you find the parametric equations for the rectangular equation #x^2+y^2-25=0# ? How do you find the parametric equations of a circle? How do you find the parametric equations of a curve? What are parametric equations used for? What is the parametric equation of an ellipse? How do you sketch the curve with parametric equations #x = sin(t)#, #y=sin^2(t)# ? How do you find the vector parametrization of the line of intersection of two planes #2x - y - z... See all questions in Introduction to Parametric Equations Impact of this question 2664 views around the world You can reuse this answer Creative Commons License