Question #50ed4

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Question #50ed4

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Answer 1 · 2018-02-22T09:58:38

$x^2-2x-4=0$

Explanation:

$"given the zeros of a polynomial say"$

$"x=a and "x=b" then the factors are"$

$(x-a)" and "(x-b)$

$"and the polynomial can be written as "$

$f(x)=k(x-a)(x-b)larrcolor(blue)"k is a multiplier"$

$"here "x=1+-sqrt5$

$rArr(x-(1+sqrt5))(x-(1-sqrt5))" are the factors"$

$rArrf(x)=k(x-1-sqrt5)(x-1+sqrt5)$

$"let "k=1$

$rArrf(x)=(x-1)^2-(sqrt5)^2$

$color(white)(rArrf(x))=x^2-2x+1-5$

$color(white)(rArrf(x))=x^2-2x-4$

$"to find the zeros solve "x^2-2x-4=0$

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Question #50ed4

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