Question #d6aae

1 Answer
A08
Sep 6, 2016

#42.4%#

Explanation:

Let an object of mass #m# has initial momentum #p_i#
Kinetic energy #KE_i=1/2p_i^2/m#
After collision let final momentum be #p_f#
Therefore kinetic energy #KE_f=1/2p_f^2/m# and
Where #=p_f# is Final momentum.
Using given #%# age of kinetic energy we have

#18%" of "KE_i=KE_f#
#=>0.18xx1/2p_i^2/m=1/2p_f^2/m#
#=>0.18xxp_i^2=p_f^2#
Taking square root of both sides we get
#0.424xxp_i=p_f#, rounded to three decimal places
Momentum is #42.4%#

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