How do you graph the line $y = -1/3x - 7$ ?

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Answer 1 · 2018-02-07T22:13:16

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y = (-1/3 xx 0) - 7$

$y = 0 - 7$

$y = -7$ or $(0, -7)$

Second Point: For $x = 3$

$y = (-1/3 xx 3) - 7$

$y = -3/3 - 7$

$y = -1 - 7$

$y = -8$ or $(3, -8)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (1/3)x + 7)(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}

How do you graph the line y = -1/3x - 7y = -1/3x - 7?