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What mass of potassium hydroxide, #KOH#, is required to make #250# #cm^3# of a #0.5# #M# solution?

1 Answer

May 22, 2016

#250# #cm^3# = #0.25# #dm^3# (= #0.25# #L#)

For a solution, #C=n/V# (concentration = number of moles/volume). Rearranging, #n=CV=0.50xx0.25=0.125# #mol#

We need #0.125# #mol# of KOH and the molar mass of KOH is #56.1# #g# #mol^-1#, so #56.1xx0.125=7.0# #g#. We need #7.0# #g# of KOH.

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