How could $O_2(g)$ react with water..?

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Answer 1 · 2016-06-04T17:26:45

You've got us. What do you propose the products to be?

Dioxygen gas will react predictably with dihydrogen gas; $O_2$ should not easily react with $H_2O$ .

I suppose formation of hydrogen peroxide could be envisaged, i.e.:

$H_2O(l) + 1/2O_2(g) rarr HO-OH(aq)$

How could O_2(g)O_2(g) react with water..?