Question #33e87

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Answer 1 · 2016-05-07T04:38:49

#pH_A# #=# #2.89#

#pH_B# #=# #7.44#

By definition, #pH# #=# #-log_10[H_3O^+]#.

#pH_A# #=# #-log_10[1.3xx10^-3]=2.89#

#pOH_B# #=# #-log_10[4.5xx10^-8]=7.44#

Since #pH+pOH=14#, #pH_B# #=# #6.56#

What does it mean when we say #log_AB=c?#

Can you tell me the values of #log_(10)10# and #log_(10)100?#