Question #33e87

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Answer 1 · 2016-05-07T04:38:49

$pH_A$ $=$ $2.89$

$pH_B$ $=$ $7.44$

By definition, $pH$ $=$ $-log_10[H_3O^+]$ .

$pH_A$ $=$ $-log_10[1.3xx10^-3]=2.89$

$pOH_B$ $=$ $-log_10[4.5xx10^-8]=7.44$

Since $pH+pOH=14$ , $pH_B$ $=$ $6.56$

What does it mean when we say $log_AB=c?$

Can you tell me the values of $log_(10)10$ and $log_(10)100?$